What is x, the length of the diagonal, to the nearest whole number

Answer:
x=16
Step-by-step explanation:
[tex]a^{2} = b^{2} + c^{2} -2bc*Cos(a)\\x^{2} = WY^{2} + WV^{2} -2*WY*WV*Cos(64)\\x^{2} = 17^{2} + 13^{2} -2*17*13*Cos(64)\\x^{2} =264.24\\x=16.25[/tex]