Answer:
98 Pa
Explanation:
Given that:
The density [tex]\rho[/tex] of the iron cube = 7860 kg/m
side of the iron cube = 1 cm = 0.01 m
density of the open fresh water [tex]\rho[/tex] = 1000 kg/m
depth of the top surface = 2.5 m
the difference in pressure between the top and bottom surfaces of the cube is determined by the hydrostatic condition;
[tex]\Delta P = P_{bottom} - P_{top}[/tex]
where
[tex]P_{bottom} = pgh \\ \\ P_{bottom} = 1000*9.8*(2.5+0.01) \\ \\ P_{bottom} = 24598 \ Pa[/tex]
[tex]P_{top} = pgh \\ \\ P_{top} = 1000*9.8*2.5 \\ \\ P_{top} =24500 \ Pa[/tex]
[tex]\Delta P = P_{bottom} - P_{top}[/tex]
[tex]\Delta P =24598 - 24500[/tex]
[tex]\Delta P =98 \ Pa[/tex]
the difference in pressure between the top and bottom surfaces of the cube is 98 Pa
