Respuesta :
Answer:
The change in temperature that occurs when 8000 J of heat is used by a mass 75 g of water is 25.4 °C
Explanation:
H = mc ΔT
m = 75 g
c = 4. 200 J/ g °C
H = 8000 J
ΔT =?
Rearranging the formula, making ΔT the subject of formula;
ΔT = H / m c
ΔT = 8000 / 75 * 4.200
ΔT = 8000 / 315
ΔT = 25.4 °C
Answer:
The change in temperature ΔT that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water is 25°C
Explanation:
The formula for change in heat supplied to a body is given as follows;
ΔH = m·C·ΔT
Where:
ΔH = Heat supplied to the body = 8000J
m = Mass of the body = 75 g
ΔT = [tex]T_{(Final)} - T_{(Initial)}[/tex] = Temperature change experienced by the body
c = Specific heat capacity of water = 4.186 J/g
Therefore, 8000 J = 75 g × 4.186 J/(g·°C) × ΔT
Therefore;
[tex]\Delta T = \frac{8000 \, J }{75 \, g \times 4.186 \, J/(g\cdot ^{\circ}C) } = 25.48 ^{\circ}C[/tex]
Hence the change in temperature ΔT that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water rounded to the nearest whole number = 25°C.
