We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.
We know that area of rectangle is width times length.
To find the area of the given rectangle we will multiply both side lengths as:
[tex]\text{Area of rectangle}=\text{Width}\times \text{Length}[/tex]
[tex]\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}[/tex]
[tex]\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2[/tex]
[tex]\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2[/tex]
[tex]\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2[/tex]
[tex]\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2[/tex]
Therefore, the area of the given rectangle would be [tex]\frac{5}{8}[/tex] square yards.
