Answer : The density of a sample of ammonia gas is, 0.572 g/L
Explanation :
To calculate the density of ammonia gas we are using ideal gas equation.
[tex]PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\frac{RT}{M}\\\\P=\frac{\rho RT}{M}[/tex]
where,
P = pressure of ammonia gas = 0.928 atm
V = volume of ammonia gas
n = number of moles of ammonia gas
w = mass of ammonia gas
R = gas constant = 0.0821 L.atm/mol.K
T = temperature of ammonia gas = [tex]63^oC=273+63=336K[/tex]
M = molar mass of ammonia gas = 17 g/mol
Now put all the given values in the above formula, we get:
[tex]P=\frac{\rho RT}{M}[/tex]
[tex]0.928atm=\frac{\rho \times (0.0821L.atm/mol.K)\times (336K)}{17g/mol}[/tex]
[tex]\rho=0.572g/L[/tex]
Therefore, the density of a sample of ammonia gas is, 0.572 g/L
