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In aqueous solution the cu 2 ion forms a complex with four ammonia molecules. Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical equation for the last step in the formation of the complex.

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Answer:

Kf = Kf = [[Cu(NH₃)₄]²⁺] / [Cu²⁺] [NH₃]⁴

Last step: [Cu(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Cu(NH₃)₄]²⁺(aq)

Explanation:

When the Cu²⁺ ion is in presence of ammonia molecules in an aqueous solution, the tetrahydrated complex is formed, thus:

Cu²⁺(aq) + NH₃(aq) ⇄ [Cu(NH₃)]²⁺(aq)               K₁

[Cu(NH₃)]²⁺ + NH₃(aq) ⇄ [Cu(NH₃)₂]²⁺(aq)         K₂

[Cu(NH₃)₂]²⁺ + NH₃(aq) ⇄ [Cu(NH₃)₃]²⁺(aq)        K₃

[Cu(NH₃)₃]²⁺ + NH₃(aq) ⇄ [Cu(NH₃)₄]²⁺(aq)        K₄ → Last step.

Global reaction:

Cu²⁺(aq) + 4 NH₃(aq) ⇄ [Cu(NH₃)₄]²⁺(aq)

And Kf is defined as:

Kf = [[Cu(NH₃)₄]²⁺] / [Cu²⁺] [NH₃]⁴

The balanced chemical equation should be

K-f = K-f = [[C-u(N-H₃)₄]²⁺] / [C-u²⁺] [N-H₃]⁴

Last step: [C-u(N-H₃)₃]²⁺ + N-H₃(a-q) ⇄ [C-u(N-H₃)₄]²⁺(a-q)

Balanced chemical equation:

At the time When the C-u²⁺ ion is in presence of ammonia molecules in an aqueous solution, so the tetrahydrated complex is formed, thus:

C-u²⁺(a-q) + N-H₃(a-q) ⇄ [C-u(N-H₃)]²⁺(a-q)               K₁

[C-u(N-H₃)]²⁺ + N-H₃(a-q) ⇄ [C-u(N-H₃)₂]²⁺(a-q)         K₂

[C-u(N-H₃)₂]²⁺ + N-H₃(a-q) ⇄ [C-u(N-H₃)₃]²⁺(a-q)        K₃

[C-u(N-H₃)₃]²⁺ + N-H₃(a-q) ⇄ [C-u(N-H₃)₄]²⁺(a-q)        K₄ → Last step.

Now

Global reaction:

C-u²⁺(a-q) + 4 N-H₃(a-q) ⇄ [C-u(N-H₃)₄]²⁺(a-q)

And K-f should be

Kf = [[C-u(N-H₃)₄]²⁺] / [C-u²⁺] [N-H₃]⁴

learn more about reaction here: https://brainly.com/question/24708300

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