Answer:
Kf = [[Co(NH₃)₆]³⁺] / [Co³⁺] [NH₃]⁶
Last step: [Cu(NH₃)₅]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₆]³⁺(aq)
Explanation:
When the Co³⁺ ion is in presence of ammonia molecules in an aqueous solution, the hexahydrated complex is formed, following the equilibriums:
Co³⁺(aq) + NH₃(aq) ⇄ [Co(NH₃)]³⁺(aq) K₁
[Co(NH₃)]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₂]³⁺(aq) K₂
[Co(NH₃)₂]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₃]³⁺(aq) K₃
[Co(NH₃)₃]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₄]³⁺(aq) K₄
[Co(NH₃)₄]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₅]³⁺(aq) K₅
[Cu(NH₃)₅]³⁺ + NH₃(aq) ⇄ [Co(NH₃)₆]³⁺(aq) K₆ → Last step
Global reaction:
Co³⁺(aq) + 6 NH₃(aq) ⇄ [Co(NH₃)₆]³⁺(aq)
Based in the global reaction, Kf is defined as:
Kf = [[Co(NH₃)₆]³⁺] / [Co³⁺] [NH₃]⁶