Respuesta :
Answer:
The probability that the selected ball is not blue is [tex]\frac{5}{6}[/tex].
The probability that the selected ball is green is [tex]\frac{1}{2}[/tex].
Step-by-step explanation:
The question is:
There are 10 brown balls, 5 blue balls and 15 green balls in a basket. If one is drawn at random, what is the probability that it is not blue? What is the probability that it is green?
Solution:
The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.
[tex]P(E)=\frac{n(E)}{N}[/tex]
The probability of the given event not taking place is known as the complement of that event.
Complement of the event E is,
1 – P (E)
The number of different color balls are as follows:
Brown = n (Br) = 10
Blue = n (Bu) = 5
Green = n (G) = 15
Total = N = 30
Compute the probability of selecting a blue ball as follows:
[tex]P(\text{Bu})=\frac{n(\text{Bu})}{N}=\frac{5}{30}=\frac{1}{6}[/tex]
Compute the probability of not selecting a blue ball as follows:
[tex]P(\text{Not Bu})=1-P(\text{Bu})[/tex]
[tex]=1-\frac{1}{6}\\\\=\frac{6-1}{6}\\\\=\frac{5}{6}[/tex]
Thus, the probability that the selected ball is not blue is [tex]\frac{5}{6}[/tex].
Compute the probability of selecting a green ball as follows:
[tex]P(\text{G})=\frac{n(\text{G})}{N}=\frac{15}{30}=\frac{1}{2}[/tex]
Thus, the probability that the selected ball is green is [tex]\frac{1}{2}[/tex].
