what is the area of the figure below ?

Answer:
Step-by-step explanation:
Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle
Down triangle:
Base b = 8 in
Height = 6 in
[tex]Area = \frac{1}{2}bh\\=\frac{1}{2}*8*6\\\\=4*6[/tex]
= 24 in²
Trapezium:
bases a = 4 in & b = 6 in
Height h = 5 in
[tex]Area=\frac{(a+b)h}{2}\\\\=\frac{(4+6)*5}{2}\\\\=\frac{10*5}{2}\\\\=5*5[/tex]
= 25 in²
Area of the upper triangle:
Base b = 6 in
Height = (8 - 5) = 3 in
[tex]Area=\frac{1}{2}bh\\\\=\frac{1}{2}*6*3\\\\=3*3[/tex]
= 9 in²
Area of the figure = 24 + 25 + 9 = 58 in²
Answer:
58 in²
Step-by-step explanation:
Separate the figure into 3 separate shapes:
The find the formulas you will use to solve each one:
Plug in the values:
Then add up all of the values:
Add the term: