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Admission to a baseball game is $4.00 for general admission and $7.00 for reserved seats. The receipts were $4814.00 for 962 paid admissions. How many of each ticket were sold?

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proz

Answer:

The number of tickets that were bought are:

general admission = 640 tickets

reserved seats = 322 tickets

Step-by-step explanation:

Let the number of general admission tickets =  x

Let the number of reserved seat tickets = y

Total number of paid admissions = 962

∴ x + y = 962 - - - - - (1)

x = 962 - y - - - - - - - (2)

Total receipts = $4814.00; at general admission ticket = $4 and reserved seat tickets = $7

4(x) + 7(y) = 4814 - - - - (3)

substituting the value of x in equation 3, using equation 2 (x = 962 - y )

4(x) + 7(y) = 4814

= 4(962 - y) + 7(y) = 4814

3848 - 4y + 7y = 4814

3848 + 3y = 4814

3y = 4814 - 3848

3y = 966

y = 966 ÷ 3 = 322

∴ y = 322

solving for the value of x in equation 2, using y = 322 ;

x = 962 - y    - - - - (2)

x = 962 - 322 = 640

∴ x = 640

Therefore, the number of tickets that were bought are:

general admission = 640 tickets

reserved seats = 322 tickets

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