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What volume of butane (C4H10) can be produced at STP, from the reaction of 13.45 g of carbon with 17.65 L of hydrogen gas at STP?
Which reactant is in excess and how much of this reactant is left over?
4 C + 5 H2 C4H10

Respuesta :

Answer:

6.277 dm3 of buatne is produced at STP.

CARBON REACTANT IS IN EXCESS BY 5.8 g

Explanation:

4 C + 5 H2 -----> C4H10

4 moles of Carbon reacts with 5 moles of hydrogen to produce 1 mole of C4H10

4 moles produces 1 mole of C4H10

4 * 12 g/mol will produce 22.4 dm3 of C4H10

48 g/mol will produce 22.4 dm3

13.45 g will produce ( 22.4 * 13.45 / 48) dm3 of C4H10

= 301.28 / 48

= 6.277 dm3 of C4H10.

2. 4 mole reacts with 5 moles of H2

48 g/mol will react with 22.4 * 5dm3

( 48 * 17.65 / 22.4 * 5) g of carbon will react with 17.65 L of H2

= 847.2 / 112

= 7.56g

7.56 g of Carbon was used to react with 17.65 L of hydrogen gas at STP.

Excess reactant is carbon ( 13.45 - 7.65 )g with 5.8 g in excess.

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