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a 3.50L sample of neon gas has a pressure of .950atm at 20c what would the volume be if the pressure increased to 1.50atm and the temperature remained constant

Respuesta :

sebassandin

Answer:

[tex]V_2=2.22L[/tex]

Explanation:

Hello,

In this case, we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:

[tex]P_1V_1=P_2V_2[/tex]

Thus, solving for the final volume, once the pressure changes, we obtain:

[tex]V_2=\frac{P_1V_1}{P_2}=\frac{3.50L*0.950atm}{1.50atm} \\\\V_2=2.22L[/tex]

Best regards.

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