Respuesta :
Answer:
The player's height is 3.02 standard deviations above the mean.
Step-by-step explanation:
Consider a random variable X following a Normal distribution with parameter μ and σ.
The procedure of standardization transforms individual scores to standard scores for which we know the percentiles (if the data are normally distributed).
Standardization does this by transforming individual scores from different normal distributions to a common normal distribution with a known mean, standard deviation, and percentiles.
A standardized score is the number of standard deviations an observation or data point is above or below the mean.
The standard score of the random variable X is:
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
These standard scores are also known as z-scores and they follow a Standard normal distribution, i.e. N (0, 1).
It is provided that the height of a successful basketball player is 196 cm.
The standard value of this height is, z = 3.02.
The z-score of 3.02 implies that the player's height is 3.02 standard deviations above the mean.
The player's height is 3.02 standard deviations above the mean.
- The calculation is as follows:
The standard scores are also called as z-scores and they follow a Standard normal distribution, i.e. N (0, 1).
Since it is given that the height of a successful basketball player is 196 cm.
Now
The standard value of this height is, z = 3.02.
So here
The z-score of 3.02 represent that the player's height is 3.02 standard deviations above the mean.
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