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A skier weighing 86.2 kg starts from rest and slides down a 32.0-m frictionless slope that is inclined at an angle of 15.0° with the horizontal. Ignore air resistance.

a. calculate the work done by gravity on the skier.

b.calculate the work done by the normal force on the skier

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Answer:

A. = 26.11kJ

B = 0N

Explanation:

Mass = 86.2kg

Distance (s) = 32m

Angle of the slope = 15°

a. Work done due to gravity

W = force * distance * angle of displacement

W = F * S * cos θ

Force = mass * acceleration due to gravity

Force = 86.2 * 9.8

Force = 844.76N

Work = 844.76 * 32 * cos 15

Work = 26111.21J

Work = 26.11kJ

b. The workdone by the normal force is equal to zero since the normal force is perpendicular to the displacement.

Hence the normal force does not act on the body.

N = 0N

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