Answer : The density of a sample of chlorine gas is, 12.59 g/L
Explanation :
To calculate the density of chlorine gas we are using ideal gas equation.
[tex]PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\frac{RT}{M}\\\\P=\frac{\rho RT}{M}[/tex]
where,
P = pressure of chlorine gas = 4.5 atm
V = volume of chlorine gas = 12.6 L
n = number of moles of chlorine gas
w = mass of chlorine gas
R = gas constant = 0.0821 L.atm/mol.K
T = temperature of chlorine gas = [tex]36^oC=273+36=309K[/tex]
M = molar mass of chlorine gas = 71 g/mol
Now put all the given values in the above formula, we get:
[tex]P=\frac{\rho RT}{M}[/tex]
[tex]4.5atm=\frac{\rho \times (0.0821L.atm/mol.K)\times (309K)}{71g/mol}[/tex]
[tex]\rho=12.59g/L[/tex]
Therefore, the density of a sample of chlorine gas is, 12.59 g/L
