Answer:
[tex]m_{Cu}=10.04gCu[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
[tex]CuO+H_2\rightarrow H_2O+Cu[/tex]
Now, since 2.844 g of water are produced, one could compute the grams of copper considering the produced water via stoichiometry and their 1:1 molar ratio:
[tex]m_{Cu}=2.844gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molCu}{1molH_2O}*\frac{63.546 g Cu}{1molCu}\\ \\m_{Cu}=10.04gCu[/tex]
Best regards.
