Respuesta :
Answer:
Null hypothesis:[tex]p=0.4[/tex]
Alternative hypothesis:[tex]p \neq 0.4[/tex]
[tex]z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98[/tex]
[tex]p_v =2*P(z>3.98)=0.0000689[/tex]
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%
Step-by-step explanation:
Information given
n=144 represent the random sample taken
X=81 represent the number of people with type A blood
[tex]\hat p=\frac{81}{144}=0.5625[/tex] estimated proportion of people with type A blood
[tex]p_o=0.4[/tex] is the value that we want to verify
[tex]\alpha=0.01[/tex] represent the significance level
z would represent the statistic
[tex]p_v{/tex} represent the p value
Hypothesis to test
We want to test if the percentage of the population having type A blood is different from 40%.:
Null hypothesis:[tex]p=0.4[/tex]
Alternative hypothesis:[tex]p \neq 0.4[/tex]
the statistic is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98[/tex]
Now we can calculate the p value with this probability taking in count the alternative hypothesis:
[tex]p_v =2*P(z>3.98)=0.0000689[/tex]
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%