Answer:
pH
[tex]= 12.54[/tex]
OH- concentration 28.84
Explanation:
KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1
In any aqueous solution, the H3O+ and OH - must satisfy the following condition -
[tex][ H_3O^+] [OH^-] = k_w[/tex]
[tex][ H_3O^+] = \frac{k_w}{ [OH^-]}[/tex]
[tex][H_3O^+] = \frac{1 * 10^{-14}}{3.5 *10^{-2}[H_3O^+] = 2.857 * 10^{-13}[/tex] M
pH =
[tex]- log [ H_3O^+]\\- log [2.857 * 10^{-13}][/tex]
pH
[tex]= - [-12.54]\\= 12.54[/tex]
pOH [tex]= 14 -[/tex] pH
pOH
[tex]= 14 - 12.54\\= 1.46[/tex]
OH concentration [tex]= antilog 1.46[/tex]
OH- concentration 28.84
