Answer:
- 637.636 mL of NaF
- 0.7014 moles of SrF2
Explanation:
[tex]C_{1}V_{1}[/tex] = [tex]C_{2}V_{2}[/tex]
Where 1 and 2 represent NaF and SrCl2 respectively; and C and V ae concentration and volume.
0.110 × V1 = 0.420 × 167
V1 = [tex]\frac{70.14}{0.110}[/tex] = 637.636 mL ≈ 0.638 L.
Mole ratio of SrF2:
mole ratio of SrCl2 : SrF2 is 1 : 1 (also, conc × vol = no. of moles )
∴ moles of SrF2 = 0.7014.
