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A frog is at the bottom of a 10-meter well. Each day he climbs up 3 meters. Each night he slides down 1 meter. On what day will he reach the top of the well and escape?

Respuesta :

ahmkha

Answer:

The 5th day he will be at 10 meters

Step-by-step explanation:

Just add 3 and subtract 1 for each day. Everyday the frog climbs 2 meters, multiply by 5 and you have 10 meters.

Hope this helped :D

On the 5th day, he will reach to the top of the well & escape.

Given that,

  • A frog is at the bottom of a 10-meter well
  • Each day he climbs up 3 meters.
  • Each night he slides down 1 meter.
  • Let us assume the number of days be x.

Based on the above information, the calculation is as follows:

x(3-1) = 10

2x = 10

x = 5

Therefore we can conclude that on the 5th day, he will reach to the top of the well & escape.

Learn more: brainly.com/question/3505647

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