1.00 mole of an ideal gas occupies a volume of 22.4 L at 0 degrees * C and 760 mmHg (STP). It is cooled to - 41 degrees * C while the pressure is increased to 805 mmHg. What is the new volume of the gas in liters?

Respuesta :

Answer:

The new volume of the gas is 17.97 liters.

Explanation:

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant, and is expressed mathematically as:

P * V = k

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, as follows:

[tex]\frac{V}{T} =k[/tex]

Gay-Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant as follows:

[tex]\frac{P}{T} =k[/tex]

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

[tex]\frac{P*V}{T} =k[/tex]

Having two different states, an initial state 1 and an final state 2, it is true:

[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]

In this case:

  • P1= 760 mmHg
  • V1= 22.4 L
  • T1= 0°C=273 °K
  • P2= 805 mmHg
  • V2=?
  • T2= -41°C= 232 °K

Replacing:

[tex]\frac{760 mmHg*22.4 L}{273 K} =\frac{805 mmHg*V2}{232K}[/tex]

Solving:

[tex]V2=\frac{760 mmHg*22.4 L}{273 K} *\frac{232 K}{805mmHg}[/tex]

V2=17.97 L

The new volume of the gas is 17.97 liters.

Answer:

18

Explanation:

Just round it