Please find the attachment.
We have been given a function [tex]f(x)=(x-5)^2+3[/tex]. We are asked to find the graph of the function.
We can see our given function is in vertex form of parabola.
The vertex form of parabola is [tex]y=a(x-h)^2+k[/tex], where point (h,k) is vertex of parabola.
Upon looking at our given function, we can see that [tex]a=1[/tex], [tex]h=5[/tex] and [tex]k=3[/tex].
Since the value of leading coefficient is positive, so our parabola will be an upward opening parabola and its vertex will be at point [tex](5,3)[/tex].
Therefore, the graph of our given function will be as shown in the attached file.
