A bottling company fills bottles with a mean of 500 mL of liquia, with a

standard deviation of 2 mL. Quality control randomly samples 20

bottles at a time. Consider the mean volume of liquid in the sample

bottles. What is the standard deviation of the sampling distribution of

this sample mean?

Respuesta :

Answer:

The standard deviation of the sampling distribution of  this sample mean is 0.447 ml.

Step-by-step explanation:

We are given that a bottling company fills bottles with a mean of 500 ml of liquia, with a  standard deviation of 2 ml. Quality control randomly samples 20  bottles at a time.

Let [tex]\bar X[/tex] = sample mean volume of liquid in bottles

The Sampling distribution of the sample mean also follows normal distribution;

As we know that ; Population mean = [tex]\mu[/tex] = 500 ml

Population Standard deviation = [tex]\sigma[/tex] = 2 ml

n = sample of bottles = 20

Now, the mean of sampling distribution is given by;

           Sample Mean, [tex]\bar X[/tex] = Population mean = 500 ml

And, standard deviation of the sampling distribution of  this sample mean is given by;

      Standard deviation =  [tex]\frac{\sigma}{\sqrt{n} }[/tex] =  [tex]\frac{2}{\sqrt{20} }[/tex] = 0.447 ml

Hence, the standard deviation of the sampling distribution of  this sample mean is 0.447 ml.