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Which is a polar form of the following parametric equations ?
x=4sin^2 theta
Y=4 sin theta cos theta

a) r=1/4sin theta cod theta
b) r=2
c)r=16sin^2 theta
d)r=4sin theta

Respuesta :

mkfme

Answer:

r=4sin(theta)

Step-by-step explanation:

x=4sin^2(theta)        y=4sin(theta)cos(theta

theta=arcsin((sqrtx)/2)

y=4sin(arcsin(sqrtx/2))cos(arcsin(sqrtx/2))

graph each to see they line up

ProfChris1

We can actually deduce here that a polar form of the parametric equations: x=4sin^2 theta and y =4 sin theta cos theta is: r=4sin(theta).

What is parametric equation?

A parametric equation refers to the equation that actually shows a group of quantities to be functions of one or more variables that are independent.

We see that the polar form x=4sin^2 theta and Y=4 sin theta cos theta is: r=4sin(theta)

Learn more about parametric equation on https://brainly.com/question/27247899

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