A triangular pyramid has lateral faces with bases of 4 meters and heights of 13 meters. The area of the base of the pyramid is 6.9 square meters. What is the surface area of the pyramid?

Respuesta :

Answer:

84.9m²

Step-by-step explanation:

Surface area Formula

[tex]SA = A + \frac{3}{2} bh[/tex]

A is the area if the base, b is the length of the base on one of the faces and h is the height of one of the faces.

[tex]a = 6.9[/tex]

[tex]b = 4[/tex]

[tex]h = 13[/tex]

Formula

[tex]SA = 6.9 + \frac{3}{2} (4 \times 13[/tex]

[tex]SA = 6.9 + \frac{3}{2} (52)[/tex]

[tex]SA = 6.9 + 78[/tex]

[tex]SA = 84.9[/tex]

The surface area is 84.9m²