Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The value of x is [tex]x = 274 \ unites[/tex]
Step-by-step explanation:
From the question we are told that
The length of the vertical length is [tex]x[/tex]
The length of the base leg is L = 330 + d units
The length of the bisecting line segment is h
The base angle is [tex]\theta = 28^o[/tex]
The angle between d and line segment is [tex]\theta_1 = 56^o[/tex]
For the first angle
[tex]Tan \theta_1 = \frac{x}{d}[/tex]
=> [tex]d = \frac{x}{Tan \theta _1}[/tex]
For the whole big triangle
[tex]Tan \theta = \frac{x}{330 + d}[/tex]
=> [tex]d = \frac{x}{Tan \theta } -330[/tex]
So equating the both d
[tex]\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330[/tex]
Substitute values
[tex]\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330[/tex]
[tex]0.6745 x = 1.880x -330[/tex]
[tex]1.20549 x = 330[/tex]
[tex]x = 274 \ unites[/tex]
