syd173
contestada

the center of the circle is (-4,5). the circle passes through (-4,3). what is it’s radius?

Respuesta :

Answer:

-The radius:

[tex]r=2[/tex]

-The result for the equation of a circle (if needed):

[tex](x+4)^2 +(y-5)^2=4[/tex]

Step-by-step explanation:

-The equation of a circle is:

[tex](x - h)^2 +(y-k)^2=r^2[/tex] where the center is [tex](h,k)[/tex], the point [tex](x,y)[/tex] and the radius is [tex]r[/tex],

-Next, use the center (-4,5) and the point (-4,3) for this equation:

[tex](-4+4)^2 +(3-5)^2=r^2[/tex]

-Then, you solve the equation:

[tex](-4+4)^2 +(3-5)^2=r^2[/tex]

[tex]0 +(-2)^2=r^2[/tex]

[tex]4 = r^2[/tex]

[tex]\sqrt{4} =\sqrt{r^2}[/tex]

[tex]2 = r[/tex]

Therefore, the result for the radius is 2.

-The result for the equation of a circle:

[tex](x+4)^2 +(y-5)^2=4[/tex]