Answer:
[tex]n_{solute}=0.406mol(NH_4)_2SO_4[/tex]
Explanation:
Hello,
In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:
[tex]n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL} \\\\n_{solute}=0.406mol(NH_4)_2SO_4[/tex]
Best regards.
