Answer:
(x + 11)(x - 11)
Step-by-step explanation:
Since [tex]x^{2}[/tex] and 121 are both perfect squares ([tex]\sqrt{x^{2}[/tex] = [tex]x[/tex] and [tex]\sqrt{121}[/tex] = [tex]11[/tex]), we can write the difference of two perfect squares a and b in the factored form: [tex](\sqrt{a} +\sqrt{b} ) (\sqrt{a} - \sqrt{b} )[/tex]. Therefore, the factored form of x^2 - 121 is (x +11)(x - 11).
Hope this helped! :)
