Answer:
12.3 moles of [tex]AlCl_{3}[/tex] are produced by reacting 18.4 moles of [tex]BaCl_{2}[/tex] .
Explanation:
Balanced reaction: [tex]2AlPO_{4}+3BaCl_{2}\rightarrow 2AlCl_{3}+Ba_{3}(PO_{4})_{2}[/tex]
According to balanced equation:
3 molecules of [tex]BaCl_{2}[/tex] produce 2 molecules of [tex]AlCl_{3}[/tex]
So [tex]3N_{A}[/tex] molecules of [tex]BaCl_{2}[/tex] produce [tex]2N_{A}[/tex] molecules of [tex]AlCl_{3}[/tex] ([tex]N_{A}[/tex] is avogadro number).
We know 1 mol of molecule = [tex]N_{A}[/tex] number of molecules.
So 3 moles of [tex]BaCl_{2}[/tex] produce 2 moles of [tex]AlCl_{3}[/tex].
Hence 18.4 moles of [tex]BaCl_{2}[/tex] produce [tex](\frac{2}{3}\times 18.4)[/tex] moles of [tex]AlCl_{3}[/tex] or 12.3 moles of [tex]AlCl_{3}[/tex] .