Answer:
[tex]m_{HgCl_2}=42.7gHgCl_2[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
[tex]HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4[/tex]
In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:
[tex]m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2[/tex]
Best regards.
