Answer:
[tex]\dfrac{9}{16}[/tex]
Step-by-step explanation:
We are given that there are a total of 80 possibilities when a card a chosen from the box which has separate cards numbered from 1 to 80.
Case 1: Number of possible cases for even number to be chosen:
[tex]\dfrac{80}{2} = 40[/tex]
because from number 1 to 80, there will be a total of 40 even numbers [tex](2, 4, 6, 8, 10, ... , 80)[/tex]
Case 2: Number of cases for an odd number below 10:
[tex]5[/tex] because below 10, the odd number possible are [tex](1,3,5,7,9)[/tex]
So, the total number of favorable cases as per the question = 45
Total Number of cases = 80
[tex]\text {Probability} = \dfrac{\text{Total Number of Favorable Cases}}{\text{Total Number of Cases}}\\\Rightarrow \dfrac{45}{80}\\\Rightarrow \dfrac{9}{16}[/tex]
So, required probability is [tex]\dfrac{9}{16}[/tex][tex].[/tex]
