The exterior angles of a triangle are (2x+10)⁰, (3x-5) ⁰ and (2x+40) ⁰
To get interior angle for each , subtract from 180
[tex]180-(2x+10)=170-2x\\180-(3x-5)=185-3x\\180-(2x+40)= 140-2x[/tex]
Sum of interior angles = 180
[tex]170-2x+185-3x+140-2x=180[/tex]
[tex]-7x+170+185+140=180\\-7x+495=180\\-7x+495-495=180-495\\-7x=-315\\x=45[/tex]
[tex]170-2x=170-2(45)=80\\185-3x=185-3(45)=50\\140-2x=140-2(45)=50[/tex]
Answer: x=45
smaller angle =50 degree
largest interior angle = 80 degrees
