The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 1300 hours and a standard deviation of 90 hours. Using the empirical rule, determine what interval of hours represents the lifespan of the middle 68% of light bulbs.

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Answer:

The interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

Step-by-step explanation:

In statistics, the 68–95–99.7 rule, also recognized as the Empirical rule, is a shortcut used to recall that 68%, 95% and 99.7% of the values lie within one, two and three standard deviations of the mean, respectively.

Then,

  • P (µ - σ < X < µ + σ) = 0.68
  • P (µ - 2σ < X < µ + 2σ) = 0.95
  • P (µ - 3σ < X < µ + 3σ) = 0.997

he random variable X can be defined as the  amount of time a certain brand of light bulb lasts.

The random variable X is normally distributed with parameters µ = 1300 hours and σ = 90 hours.

Compute the interval of hours that represents the lifespan of the middle 68% of light bulbs as follows:

[tex]P (\mu - \sigma < X < \mu + \sigma) = 0.68\\\\P(1300-90<X<1300+90)+0.68\\\\P(1210<X<1390)=0.68[/tex]

Thus, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

This question is based on the statistics. Therefore, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

Given:

The amount of time a certain brand of light bulb lasts is normally distributed with a mean of 1300 hours and a standard deviation of 90 hours.

According to the question,

As we know that, In statistics, the 68–95–99.7 rule, also called as the Empirical rule states that, for a normal distribution, all observed data will fall within three standard deviations (denoted by σ) of the mean or average (denoted by µ).

Therefore,

P (µ - σ < X < µ + σ) = 0.68

P (µ - 2σ < X < µ + 2σ) = 0.95

P (µ - 3σ < X < µ + 3σ) = 0.997

The random variable X can be defined as, the amount of time a certain brand of light bulb lasts and the random variable X is normally distributed with parameters µ = 1300 hours and σ = 90 hours.

Now, calculate the interval of hours that represents the lifespan of the middle 68% of light bulbs as follows:

⇒ P ( µ  - σ < X < µ  + σ ) = 0.68

⇒ P ( 1300  - 90 < X < 1300  + 90 ) = 0.68

⇒ P( 1210 < X < 1390) = 0.68

Therefore, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

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