Answer:
137.8g of Al(OH)₃ reacts
Explanation:
Based on the reaction:
3HCl + Al(OH)₃ → 3H₂O + AlCl₃
3 moles of HCl reacts per mole of Al(OH)₃
If 5.30 moles of HCl react, moles of Al(OH)₃ are:
5.30 mol HCl × (1 mol Al(OH)₃ / 3 mol HCl) = 1.767 moles of Al(OH)₃
In mass:
1.767 moles of Al(OH)₃ × (78g / 1mol) = 137.8g of Al(OH)₃ reacts
