Respuesta :
Let b represent cost of blue beads and s represent cost of silver beads.
We have been given that Mia is making a necklace using two types of beads. Buying 40 blue beads and 20 silver beads will cost $10. We can represent this information in an equation as:
[tex]40b+20s=10...(1)[/tex]
Buying 20 blue beads and 40 silver beads will cost $14. We can represent this information in an equation as:
[tex]20b+40s=14...(2)[/tex]
Multiplying equation (2) with 2, we will get:
[tex]40b+80s=28...(2)[/tex]
Upon subtracting equation (2) from equation (1), we will get:
[tex]40b-40b+20s-80s=10-28[/tex]
[tex]-60s=-18[/tex]
[tex]\frac{-60s}{-60}=\frac{-18}{-60}[/tex]
[tex]s=0.3[/tex]
Therefore, the cost of silver beads is $0.3.
Upon substituting [tex]s=0.3[/tex] in equation (1), we will get:
[tex]40b+20(0.3)=10[/tex]
[tex]40b+6=10[/tex]
[tex]40b+6-6=10-6[/tex]
[tex]40b=4[/tex]
[tex]\frac{40b}{40}=\frac{4}{40}[/tex]
[tex]b=0.1[/tex]
Therefore, the cost of blue beads is $0.1.
