Answer:
[H⁺] = 1.58x10⁻⁶M; [OH⁻] = 6.31x10⁻⁹M.
pH = 8.23; pOH = 5.77
Explanation:
pH is defined as -log [H⁺] and also you have 14 = pH + pOH
Thus, for a solution of pH = 5.80.
5.80 = -log [H⁺] → [H⁺] = 10^-(5.80) = 1.58x10⁻⁶M
pOH = 14-5.80 = 8.20 → [OH⁻] = 10^-(8.20) = 6.31x10⁻⁹M
Thus, for a solution of [H⁺] = 5.90x10⁻⁹M and pH = -log 5.90x10⁻⁹M = 8.23
And pOH = 14-8.23 = 5.77