Answer:
Balanced reaction: [tex]3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O[/tex]
S is oxidized and N is reduced.
[tex]NO_{3}^{-}[/tex] is the oxidizing agent and ZnS is the reducing agent.
Explanation:
Reaction: [tex]ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO[/tex]
[tex]\Rightarrow[/tex] Oxidation: [tex]ZnS\rightarrow Zn^{2+}+S[/tex]
Balance charge: [tex]ZnS-2e^{-}\rightarrow Zn^{2+}+S[/tex] ...............(1)
[tex]\Rightarrow[/tex] Reduction: [tex]NO_{3}^{-}\rightarrow NO[/tex]
Balance H and O in acidic medium : [tex]NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O[/tex]
Balance charge: [tex]NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O[/tex] ...............(2)
[[tex]3\times[/tex]Equation-(1)] + [ [tex]2\times[/tex]Equation-(2)]:
[tex]3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O[/tex]
Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.
Oxidation number of N decreases from (+5) to (+2) for the conversion of [tex]NO_{3}^{-}[/tex] to NO. Therefore N is reduced.
[tex]NO_{3}^{-}[/tex] consumes electron from ZnS. Therefore [tex]NO_{3}^{-}[/tex] is the oxidizing agent and ZnS is the reducing agent.
The balanced redox reaction equation shows the electrons lost/gained.
A redox reaction equation is said to be balanced when the number of electrons gained is equal to the number of electrons lost. The specie that looses electrons is the reducing agent while the specie that gains electrons is the oxidizing agent.
Having known these, the balanced reaction equation for the reaction between zinc sulfide and nitrate ion in aqueous acid solution is;
[tex]3ZnS + 2NO3^- + 8H^+ ----> 3Zn^{2+} + 2NO+ 3S + 4H2O[/tex]
Learn more: https://brainly.com/question/2510654
