Answer:
Hey!
Your answer lies below!
Step-by-step explanation:
FORMULAS: n
t
h
term is found by a
n
=
a
1
+
(
n
−
1
)
d
The sum of terms is found by S
n
=
(
a
1
+
a
n
)
n / 2
soo…
a
1
=
19 *our first term...*
a
4
=
55 *our fourth term...*
Using the formula: a
4
=
a
1
+
3
d
We manage to calculate the actual difference of:
d
=
a
4
−
a
1 / 3
=
55
−
19 / 3 (division)
=
12
d=a4−a13=55−193 =12
Which now results in the that our remaining two terms are:
a
2
=
a
1
+
d
=
19
+
12
=
31
a3 =
a
1
+
2
d
=
19
+
12
⋅
2
=
43
HOPE THIS HELPS!!
