Answer:Trying to present a possible Answer
We know that the molar mass of carbon and hydrogen are
C
=
12
g/mol
and
H
=
1
g/mol
When Carbon Hydrogen mass ratio is 11.89
The ratio of no. Of atoms of C and H is given by
C
H
=
11.89
12
1
1
≈
1
1
So empirical formula
C
H
→
possible
Now from the list
a)
When Carbon Hydrogen mass ratio is 2.5
The ratio of no. Of atoms of C and H is given by
C
H
=
2.5
12
1
1
≈
5
24
So empirical formula
C
5
H
24
→
not possible
Beceause the molecular formula of alkane with 5 C-atoms in the molecule is
C
5
H
12
. So the maximum number of hydrogen with 5 C should not exceed 12.
b)
When Carbon Hydrogen mass ratio is 3.97
The ratio of no. Of atoms of C and H is given by
C
H
=
3.97
12
1
1
≈
1
3
So empirical formula
C
H
3
→
possible
This is found in ethane having MF
C
2
H
6
c)
When Carbon Hydrogen mass ratio is 4.66
The ratio of no. Of atoms of C and H is given by
C
H
=
4.66
12
1
1
≈
7
18
So empirical formula
C
7
H
18
→
not possible
Since maximum number of H with 7C-atoms is
7
×
2
+
2
=
16
.So it has been exceeded.
d)
When Carbon Hydrogen mass ratio is 7.89
The ratio of no. Of atoms of C and H is given by
C
H
=
7.89
12
1
1
≈
2
3
So empirical formula
C
2
H
3
→
possible
Since the molecular formula of butyne or butadiene
C
4
H
6
supports the empirical formula
C
2
H
3
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