Answer:
The force exerted on the [tex]q_1[/tex] is [tex]F = 2.25*10^{3} \ N[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 2.34*10^{-3} \ m^2[/tex]
The magnitude of charge placed on them is [tex]q = 7.07 * 10^{-7} C[/tex]
The charge placed between the plate is [tex]q_1 = 6.62 *10^{-5} C[/tex]
The electric field generated around the plate is mathematically represented as
[tex]E = \frac{q}{A \epsilon_o}[/tex]
Substituting values
[tex]E = \frac{7.07*10^{-7}}{2.34*10^{-3} * 8.85 *10^{-12}}[/tex]
[tex]E = 34*10^{6} \ V/m[/tex]
The force exerted the charge [tex]q_1[/tex] is mathematically represented as
[tex]F = q_1 * E[/tex]
Substituting values
[tex]F = 6.62 *10^{-5} * 34*10^{6}[/tex]
[tex]F = 2.25*10^{3} \ N[/tex]
