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How much water needs to be added to an 18.0 M stock solution of sodium hydroxide in order to make 450.0 mL of 0.250 M sodium hydroxide solution?

Respuesta :

SvetkaChem

Answer:

443.8 mL of water

Explanation:

M1V1 = M2V2

18.0 M*V1 = 0.250M*450.0mL

V1 = 0.250*450.0/18.0 = 6.25 mL solution of 18.0 we need to take to make 450.0 mL of 0.250 M NaOH.

450.0 mL - 6.25 mL = 443.75  mL ≈443.8 mL of water should be added

Raineyvonahnen

Answer:

443.8 mL of water

Explanation:

on chem

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