We have that
Option a is Correct
The values of the root is
[tex]v=1\\\\v=2[/tex]
From the question we are told that
The function
[tex]v^2-3v+2=0[/tex]
Generally, the equation for Quadratic equation is mathematically given by
[tex]v=\frac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]
Therefore
[tex]v=\frac{-(-3) \pm\sqrt{(-3)^2-4(1)(2)}}{2(1)}[/tex]
Solving the Quadratic equation we have the root values as
[tex]v=1\\\\v=2[/tex]
In conclusion
The correct option is Option a
The values of the root is
[tex]v=1\\\\v=2[/tex]
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