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A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wider bandwidth, a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz?

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Answer:

A.) Phase in degree= 40° ; phase in radian

B.) Bandwidth is the same.

Explanation:

1 complete cycle = 360°

Therefore, 1/9 of a cycle :

Phase in degree ;

(1/9) × 360° = 40°

Phase in radian:

40 × (2π/360)

80π/360

= 0.222πrad

0.698rad

In simple terms, A bandwidth could be explained as the difference between the upper and lower frequencies of the signal. However, the signal described above is a simple signal with no upper or lower frequency boundary.

hence, the bandwidth is assumed to be the same.

raphealnwobi

The bandwidth of  a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz is 0.

a) Each complete cycle measures 360 degrees. Hence, 1/9 cycle is:

1/9 cycle = 1/9 × 360° = 40°

Each complete cycle measures 2π radian. Hence, 1/9 cycle is:

1/9 cycle = 1/9 × 2π = 2π/9 radian

b) The bandwidth of a sine wave is 0. Hence the bandwidth of  a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz is 0.

Find out more at: https://brainly.com/question/13440320

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