Answer:
893K=620 °C
Explanation:
PV=nRT
P=nRT/V
P= (1 mol* 0.0821* 298K)/15L P=1.63 atm
T=PV/nR
T=(1.63 atm*45 L)/(1 mol*0.0821)
T= 893K=620 °C
Considering the Charles's Law, the new temperature must be 894 K (or 621 C).
Charles's Law consists of the relationship between the volume and the temperature of a certain amount of ideal gas, which is kept at a constant pressure.
This law determines that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.
In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
[tex]\frac{V}{T}=k[/tex]
Considering an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
In this case, you know:
Replacing in Charles's Law:
[tex]\frac{15 L}{298 K}=\frac{45 L}{T2}[/tex]
Solving:
[tex]T2x\frac{15 L}{298 K}=45 L[/tex]
[tex]T2=\frac{45 L}{\frac{15 L}{298 K}}[/tex]
T2=894 K= 621 C
Finally, the new temperature must be 894 K (or 621 C).
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