Answer:
Probability that a house has a hot tub given that it has a pool is 55%.
Step-by-step explanation:
We are given that in New York State, 38% of the houses have a pool and 21% of the houses have both a pool and a hot tub.
Let the probability that houses have a pool = P(A) = 0.38
Also, let B = event that houses have a hot tub
Probability that houses have both a pool and a hot tub = [tex]P(A \bigcap B)[/tex] = 0.21
Now, the conditional probability that a house has a hot tub given that it has a pool is given by = P(B / A)
As we know that; P(B / A) = [tex]\frac{P(A \bigcap B)}{P(A) }[/tex]
= [tex]\frac{0.21}{0.38}[/tex]
= 0.553 ≈ 55%
Hence, the probability that a house has a hot tub given that it has a pool is 55%.
