Answer:
Surface area of prism is 382.5 sq. in.
Step-by-step explanation:
Total Surface area of prism = Sum of area of all faces
So, Area of triangle ABC = [tex]\frac{1}{2} \times Base \times height[/tex]
Area of triangle ABC =[tex]\frac{1}{2} \times AB \times BC[/tex]
Area of triangle ABC = [tex]\frac{1}{2} \times 9 \times 10 =45 in^2[/tex]
Area of triangle DEF = Area of triangle ABC =45 sq. in.
Area of rectangular base ACED=[tex]Length \times Breadth = AC \times CE=13.5 \times 9 =121.5[/tex]
Area of ABFD = [tex]Length \times Breadth = AB \times BF=9 \times 9 =81 sq. in.[/tex]
Area of CBFE=[tex]Length \times Breadth = CB \times BF=10 \times 9 =90 sq. in.[/tex]
Total Surface area of prism = Sum of area of all faces =45+45+121.5+81+90=382.5 sq. in.
Hence Surface area of prism is 382.5 sq. in.
