Answer:
[tex]V_2=4.0132L[/tex]
Explanation:
Hello,
In this case, the original solution had a volume of 93.2 mL which in L is:
[tex]V_1=93.2mL*\frac{1L}{1000mL}=0.0932L[/tex]
Now, since 3.92 L of water were added, the volume of the resulting solution will include the added volume of water as shown below:
[tex]V_2=V_1+V_{H_2O}=3.92L+0.0932L\\\\V_2=4.0132L[/tex]
Moreover, the resulting molarity of the potassium fluoride diluted solution will be:
[tex]M_2=\frac{M_1V_1}{V_2}=\frac{0.0932L*2.03M}{4.0132L}\\ \\M_2=0.0471M[/tex]
Best regards.
