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A coil consists of 180 turns of wire. Each turn is a square of side d=30 cm, and a uniform magnetic field directed perpendicular to the plane of the coil is turned on. If the field changes linearly from 0 to 1.22 T in 0.06s, what is the magnitude of the induced force in the coil while the field is changing?

Respuesta :

Answer:

Emf induced i equal to 329.4 volt

Explanation:

Note : Here i think we have to find emf induced in the coil

Number of turns in the coil N= 180

Sides of square d = 30 cm = 0.3 m

So area of the square [tex]A=0.3\times 0.3=0.09m^2[/tex]

Magnetic field is changes from 0 to 1.22 T

Therefore [tex]dB=1.22-0=1.22T[/tex]

Time interval in changing the magnetic field dt = 0.06 sec

Induced emf is given by

[tex]e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}[/tex]

[tex]e=-180\times 0.09\times \frac{1.22}{0.06}=329.4volt[/tex]

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