Which of the following is the graph of y = cosine (2 (x + pi))?
On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum of negative 1 and a maximum of 1. It goes through 2 cycles at pi.
On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum of negative 1 and a maximum of 1. It goes through 1 cycle at pi.
On a coordinate plane, a curve crosses the y-axis at (0, 1). It has a minimum of negative 1 and a maximum of 1. It goes through 1 cycle at 4 pi.
On a coordinate plane, a curve crosses the y-axis at (0, 1). It has a minimum of negative 1 and a maximum of 1. It goes through 2 cycles at 2 pi.

On a coordinate plane, a curve crosses the y-axis at (0, 1). It has a minimum of negative 1 and a maximum of 1. It goes through 2 cycles at 2 pi.

Which is the graph of the given function?

Here we have the function:

y = cos(2*(x + pi))

First, let's distribute the product in the argument of the cosine:

y = cos(2x + 2pi).

Now, notice that 2pi is the period of a cosine function, then:

cos(2x) = cos(2x + 2pi)

Then we can write:

y = cos(2x)

Now, the y-intercept is:

y = cos(2*0) = 1

And because the factor of 2 inside the argument, it goes through 2 cycle at 2pi (instead of 1 cycle, like a normal cosine).

Then the correct option is:

"On a coordinate plane, a curve crosses the y-axis at (0, 1). It has a minimum of negative 1 and a maximum of 1. It goes through 2 cycles at 2 pi."

If you want to learn more about cosine functions, you can read:

https://brainly.com/question/8120556